4x^2=-3(4x+3)

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Solution for 4x^2=-3(4x+3) equation: 



4x^2=-3(4x+3)

We move all terms to the left:

4x^2-(-3(4x+3))=0



We calculate terms in parentheses: -(-3(4x+3)), so:

-3(4x+3)

We multiply parentheses

-12x-9

Back to the equation:

-(-12x-9)



We get rid of parentheses

4x^2+12x+9=0

a = 4; b = 12; c = +9;
Δ = b2-4ac
Δ = 122-4·4·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{8}=-1+1/2$

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